Graph Y 1 3x 3

In order to graph y=%281%2F3%29%2Ax-3

we merely need to plug in two points to draw the line

So lets plug in some points

Plug in ten=-nine

y=%281%2F3%29%2A%28-9%29-3

y=-9%2F3-3 Multiply

y=-18%2F3 Add

y=-6 Reduce

So here's one point (-9,-6)

At present lets detect another point

Plug in x=-6

y=%281%2F3%29%2A%28-6%29-3

y=-6%2F3-3 Multiply

y=-15%2F3 Add

y=-5 Reduce

So here's another point (-six,-five). Add this to our graph

Now describe a line through these points

Then this is the graph of y=%281%2F3%29%2Ax-3 through the points (-9,-6) and (-6,-5)

So from the graph we can run into that the slope is 1%2F3 (which tells us that in order to become from betoken to betoken we have to kickoff at one point and get up one units and to the correct 3 units to get to the side by side point) the y-intercept is (0,)and the ten-intercept is (,0)

We could graph this equation another way. Since b=-3 this tells us that the y-intercept (the signal where the graph intersects with the y-axis) is (0,).

And so nosotros have 1 point (0,)

Now since the slope is 1%2F3 , this means that in order to go from point to betoken we can employ the slope to do so. So starting at (0,), we tin go upward ane units

and to the correct 3 units to get to our side by side point